Generate Schema from Example Value
If you want a schema for a type that can't/doesn't implement JsonSchema
, but does implement serde::Serialize
, then you can generate a JSON schema from a value of that type. However, this schema will generally be less precise than if the type implemented JsonSchema
- particularly when it involves enums, since schemars will not make any assumptions about the structure of an enum based on a single variant.
use schemars::schema_for_value;
use serde::Serialize;
#[derive(Serialize)]
pub struct MyStruct {
pub my_int: i32,
pub my_bool: bool,
pub my_nullable_enum: Option<MyEnum>,
}
#[derive(Serialize)]
pub enum MyEnum {
StringNewType(String),
StructVariant { floats: Vec<f32> },
}
fn main() {
let schema = schema_for_value!(MyStruct {
my_int: 123,
my_bool: true,
my_nullable_enum: Some(MyEnum::StringNewType("foo".to_string()))
});
println!("{}", serde_json::to_string_pretty(&schema).unwrap());
}
Click to see the output JSON schema...
{
"$schema": "http://json-schema.org/draft-07/schema#",
"title": "MyStruct",
"examples": [
{
"my_bool": true,
"my_int": 123,
"my_nullable_enum": {
"StringNewType": "foo"
}
}
],
"type": "object",
"properties": {
"my_bool": {
"type": "boolean"
},
"my_int": {
"type": "integer"
},
"my_nullable_enum": true
}
}
Note that the schema for the enum is not very useful in this case, since schemars doesn't know anything about the second variant.